Let’s say you need to select 3 vehicles from 5 cars and 4 bicycles, in which we need at least 1 car and 1 bicycle. Wow!!! We now know the correct approach to solve this type of question.ġ. (2 paperback AND 1 hardback) OR (1 paperback AND 2 hardback) O Thus, Total possible ways of collecting 3 books = Thus, in this case we will write down all the possible ways of having paperback and hardback books (keeping in mind the constraint: we need at least one book of each type).In scenarios like these where there are multiple categories and we need a mix of all the types, in such situations, we will first jot down all the possible cases in which all the types can be mixed or collected together. In questions like these, we have two categories: Hardback and Paperback. ![]() How to avoid Double Counting in such cases? We call this counting of some extra cases as double or multiple counting. Thus, we repeated 4 cases and that is why we were getting the wrong answer to the actual question.
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